8p^2-48=-40p

Solution for 8p^2-48=-40p equation:

8p^2-48=-40p

We move all terms to the left:

8p^2-48-(-40p)=0

We get rid of parentheses

8p^2+40p-48=0

a = 8; b = 40; c = -48;
Δ = b2-4ac
Δ = 402-4·8·(-48)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-56}{2*8}=\frac{-96}{16}
=-6
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+56}{2*8}=\frac{16}{16}
=1
$